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Functions question

2025 · Shift 1 · Q22
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  5. /2025 · Shift 1 · Q22

Functions question

2025 · Shift 1 · Q22

JEE AdvancedMathematicsFunctionsMultiple correct+4 / −2
Let ℕ denote the set of all natural numbers, and ℤ denote the set of all integers. Consider the functions f: ℕ → ℤ and g: ℤ → ℕ defined by f(n)={(n+1)2if n is odd,(4−n)2if n is even,f(n) = \begin{cases} \frac{(n + 1)}{2} & \text{if } n \text{ is odd,} \\ \frac{(4-n)}{2} & \text{if } n \text{ is even,} \end{cases}f(n)={2(n+1)​2(4−n)​​if n is odd,if n is even,​ and g(n)={3+2nif n≥0,−2nif n<0.g(n) = \begin{cases} 3 + 2n & \text{if } n \ge 0 , \\ -2n & \text{if } n \lt 0 . \end{cases}g(n)={3+2n−2n​if n≥0,if n<0.​ Define (g∘f)(n)=g(f(n))(g \circ f)(n) = g(f(n))(g∘f)(n)=g(f(n)) for all n∈Nn \in \mathbb{N}n∈N, and (f∘g)(n)=f(g(n))(f \circ g)(n) = f(g(n))(f∘g)(n)=f(g(n)) for all n∈Zn \in \mathbb{Z}n∈Z. Then which of the following statements is (are) TRUE?
  1. A
    g ∘\circ∘ f is NOT one-one and g ∘\circ∘ f is NOT onto
  2. B
    f ∘\circ∘ g is NOT one-one but f ∘\circ∘ g is onto
  3. C
    g is one-one and g is onto
  4. D
    f is NOT one-one but f is onto
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