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Functions question

2024 · Shift 2 · Q25
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  5. /2024 · Shift 2 · Q25

Functions question

2024 · Shift 2 · Q25

JEE AdvancedMathematicsFunctionsNumerical+4 / −1
Let f:R→Rf: \mathbb{R} \rightarrow \mathbb{R}f:R→R be a function such that f(x+y)=f(x)+f(y)f(x+y)=f(x)+f(y)f(x+y)=f(x)+f(y) for all x,y∈Rx, y \in \mathbb{R}x,y∈R, and g:R→(0,∞)g: \mathbb{R} \rightarrow(0, \infty)g:R→(0,∞) be a function such that g(x+y)=g(x)g(y)g(x+y)=g(x) g(y)g(x+y)=g(x)g(y) for all x,y∈Rx, y \in \mathbb{R}x,y∈R. If f(−35)=12f\left(\frac{-3}{5}\right)=12f(5−3​)=12 and g(−13)=2g\left(\frac{-1}{3}\right)=2g(3−1​)=2, then the value of (f(14)+g(−2)−8)g(0)\left(f\left(\frac{1}{4}\right)+g(-2)-8\right) g(0)(f(41​)+g(−2)−8)g(0) is ‾\underline{\hspace{2cm}}​.
Numerical answer
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