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Functions question

2024 · Shift 2 · Q27
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  5. /2024 · Shift 2 · Q27

Functions question

2024 · Shift 2 · Q27

JEE AdvancedMathematicsFunctionsNumerical+4 / −1
Let the function f:R→Rf: \mathbb{R} \rightarrow \mathbb{R}f:R→R be defined by f(x)=sin⁡xeπx(x2023+2024x+2025)(x2−x+3)+2eπx(x2023+2024x+2025)(x2−x+3).f(x)=\frac{\sin x}{e^{\pi x}} \frac{\left(x^{2023}+2024 x+2025\right)}{\left(x^2-x+3\right)}+\frac{2}{e^{\pi x}} \frac{\left(x^{2023}+2024 x+2025\right)}{\left(x^2-x+3\right)} .f(x)=eπxsinx​(x2−x+3)(x2023+2024x+2025)​+eπx2​(x2−x+3)(x2023+2024x+2025)​. Then the number of solutions of f(x)=0f(x)=0f(x)=0 in R\mathbb{R}R is ‾\underline{\hspace{2cm}}​.
Numerical answer
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