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Differential Equations question

2014 · Shift 2 · Q33
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  5. /2014 · Shift 2 · Q33

Differential Equations question

2014 · Shift 2 · Q33

JEE AdvancedMathematicsDifferential EquationsMCQ+3 / −1
The function y=f(x)y=f(x)y=f(x) is the solution of the differential equation dydx+xyx2−1=x4+2x1−x2 {{dy} \over {dx}} + {{xy} \over {{x^2} - 1}} = {{{x^4} + 2x} \over {\sqrt {1 - {x^2}} }}\,dxdy​+x2−1xy​=1−x2​x4+2x​ in (−1,1)(-1,1)(−1,1) satisfying f(0)=0f(0)=0f(0)=0. Then ∫−3232f(x) d(x)\int\limits_{ - {{\sqrt 3 } \over 2}}^{{{\sqrt 3 } \over 2}} {f\left( x \right)} \,d\left( x \right)−23​​∫23​​​f(x)d(x) is
  1. A
    π3−32{\pi \over 3} - {{\sqrt 3 } \over 2}3π​−23​​
  2. B
    π3−34{\pi \over 3} - {{\sqrt 3 } \over 4}3π​−43​​
  3. C
    π6−34{\pi \over 6} - {{\sqrt 3 } \over 4}6π​−43​​
  4. D
    π6−32{\pi \over 6} - {{\sqrt 3 } \over 2}6π​−23​​
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