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Differential Equations question

2011 · Shift 2 · Q32
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  5. /2011 · Shift 2 · Q32

Differential Equations question

2011 · Shift 2 · Q32

JEE AdvancedMathematicsDifferential EquationsNumerical+4 / −1
Let y′(x)+y(x)g′(x)=g(x),g′(x),y(0)=0,x∈R,y'\left( x \right) + y\left( x \right)g'\left( x \right) = g\left( x \right),g'\left( x \right),y\left( 0 \right) = 0,x \in R,y′(x)+y(x)g′(x)=g(x),g′(x),y(0)=0,x∈R, where f′(x)f'(x)f′(x) denotes df(x)dx{{df\left( x \right)} \over {dx}}dxdf(x)​ and g(x)g(x)g(x) is a given non-constant differentiable function on RRR with g(0)=g(2)=0.g(0)=g(2)=0.g(0)=g(2)=0. Then the value of y(2)y(2)y(2) is
Numerical answer
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