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Differential Equations question

2008 · Shift 2 · Q29
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  1. PYQ Library
  2. /JEE Advanced
  3. /Mathematics
  4. /Differential Equations
  5. /2008 · Shift 2 · Q29

Differential Equations question

2008 · Shift 2 · Q29

JEE AdvancedMathematicsDifferential EquationsMCQ+3 / −1
Let a solution y=y(x)y=y(x)y=y(x) of the differential equation, xx2−1  dy−yy2−1 dx=0x\sqrt {{x^2} - 1} \,\,dy - y\sqrt {{y^2} - 1} \,dx = 0xx2−1​dy−yy2−1​dx=0 satify y(2)=23.y\left( 2 \right) = {2 \over {\sqrt 3 }}.y(2)=3​2​. STATEMENT-1 : y(x)=sec⁡(sec⁡−1x−π6)y\left( x \right) = \sec \left( {{{\sec }^{ - 1}}x - {\pi \over 6}} \right)y(x)=sec(sec−1x−6π​) and STATEMENT-2 : y(x)y\left( x \right)y(x) given by 1y=23x−1−1x2{1 \over y} = {{2\sqrt 3 } \over x} - \sqrt {1 - {1 \over {{x^2}}}}y1​=x23​​−1−x21​​
  1. A
    STATEMENT-1 is True, STATEMENT-2 is True;STATEMENT-2 is a correct explanation for STATEMENT-1
  2. B
    STATEMENT-1 is True, STATEMENT-2 is True;STATEMENT-2 is NOT a correct explanation for STATEMENT-1
  3. C
    STATEMENT-1 is True, STATEMENT-2 is False
  4. D
    STATEMENT-1 is False , STATEMENT-2 is True
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