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Differential Equations question

2024 · Shift 1 · Q18
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  2. /JEE Advanced
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  5. /2024 · Shift 1 · Q18

Differential Equations question

2024 · Shift 1 · Q18

JEE AdvancedMathematicsDifferential EquationsMCQ+3 / −1
Let f(x)f(x)f(x) be a continuously differentiable function on the interval (0,∞)(0, \infty)(0,∞) such that f(1)=2f(1)=2f(1)=2 and lim⁡t→xt10f(x)−x10f(t)t9−x9=1\lim\limits_{t \rightarrow x} \frac{t^{10} f(x)-x^{10} f(t)}{t^9-x^9}=1t→xlim​t9−x9t10f(x)−x10f(t)​=1 for each x>0x\gt 0x>0. Then, for all x>0,f(x)x\gt 0, f(x)x>0,f(x) is equal to :
  1. A
    3111x−911x10\frac{31}{11 x}-\frac{9}{11} x^{10}11x31​−119​x10
  2. B
    911x+1311x10\frac{9}{11 x}+\frac{13}{11} x^{10}11x9​+1113​x10
  3. C
    −911x+3111x10\frac{-9}{11 x}+\frac{31}{11} x^{10}11x−9​+1131​x10
  4. D
    1311x+911x10\frac{13}{11 x}+\frac{9}{11} x^{10}11x13​+119​x10
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