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Definite Integration question

2023 · Shift 2 · Q25
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  5. /2023 · Shift 2 · Q25

Definite Integration question

2023 · Shift 2 · Q25

JEE AdvancedMathematicsDefinite IntegrationNumerical+4 / −1
For x∈Rx \in \mathbb{R}x∈R, let tan⁡−1(x)∈(−π2,π2)\tan ^{-1}(x) \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)tan−1(x)∈(−2π​,2π​). Then the minimum value of the function f:R→Rf: \mathbb{R} \rightarrow \mathbb{R}f:R→R defined by f(x)=∫0xtan⁡−1xe(t−cos⁡t)1+t2023dtf(x)=\int\limits_0^{x \tan ^{-1} x} \frac{e^{(t-\cos t)}}{1+t^{2023}} d tf(x)=0∫xtan−1x​1+t2023e(t−cost)​dt is :
Numerical answer
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