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Definite Integration question

2021 · Shift 2 · Q22
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  5. /2021 · Shift 2 · Q22

Definite Integration question

2021 · Shift 2 · Q22

JEE AdvancedMathematicsDefinite IntegrationMultiple correct+4 / −2
Let f:[−π2,π2]→Rf:\left[ { - {\pi \over 2},{\pi \over 2}} \right] \to Rf:[−2π​,2π​]→R be a continuous function such that f(0)=1f(0) = 1f(0)=1 and ∫0π3f(t)dt=0\int_0^{{\pi \over 3}} {f(t)dt = 0}∫03π​​f(t)dt=0. Then which of the following statements is(are) TRUE?
  1. A
    The equation f(x)−3cos⁡3x=0f(x) - 3\cos 3x = 0f(x)−3cos3x=0 has at least one solution in (0,π3)\left( {0,{\pi \over 3}} \right)(0,3π​)
  2. B
    The equation f(x)−3sin⁡3x=−6πf(x) - 3\sin 3x = - {6 \over \pi }f(x)−3sin3x=−π6​ has at least one solution in (0,π3)\left( {0,{\pi \over 3}} \right)(0,3π​)
  3. C
    lim⁡x→0x∫0xf(t)dt1−ex2=−1\mathop {\lim }\limits_{x \to 0} {{x\int_0^x {f(t)dt} } \over {1 - {e^{{x^2}}}}} = - 1x→0lim​1−ex2x∫0x​f(t)dt​=−1
  4. D
    lim⁡x→0sin⁡x∫0xf(t)dtx2=−1\mathop {\lim }\limits_{x \to 0} {{\sin x\int_0^x {f(t)dt} } \over {{x^2}}} = - 1x→0lim​x2sinx∫0x​f(t)dt​=−1
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