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Thermodynamics question

2012 · Shift 1 · Q17
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Thermodynamics question

2012 · Shift 1 · Q17

JEE AdvancedChemistryThermodynamicsMultiple correct+4 / −2
For an ideal gas, consider only P-V work in going from an initial state X to the final state Z. The final state Z can be reached by either of the two paths shown in the figure. Which of the following choice(s) is(are) correct? (Take Δ\DeltaΔ S as change in entropy and WWW as work done) IIT-JEE 2012 Paper 1 Offline Chemistry - Thermodynamics Question 15 English
  1. A
    ΔSX→Z=ΔSX→Y+ΔSY→Z\Delta {S_{X \to Z}} = \Delta {S_{X \to Y}} + \Delta {S_{Y \to Z}}ΔSX→Z​=ΔSX→Y​+ΔSY→Z​
  2. B
    ΔWX→Z=ΔWX→Y+ΔWY→Z\Delta {W_{X \to Z}} = \Delta {W_{X \to Y}} + \Delta {W_{Y \to Z}}ΔWX→Z​=ΔWX→Y​+ΔWY→Z​
  3. C
    WX→Y→Z=WX→Y{W_{X \to Y \to Z}} = {W_{X \to Y}}WX→Y→Z​=WX→Y​
  4. D
    ΔSX→Y→Z=ΔSX→Y\Delta {S_{X \to Y \to Z}} = \Delta {S_{X \to Y}}ΔSX→Y→Z​=ΔSX→Y​
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