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Some Basic Concepts of Chemistry question

2009 · Shift 1 · Q2
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Some Basic Concepts of Chemistry question

2009 · Shift 1 · Q2

JEE AdvancedChemistrySome Basic Concepts of ChemistryMCQ+1 / −0.25
Given that the abundances of isotopes 54Fe, 56Fe and 57Fe are 5%, 90% and 5%, respectively, the atomic mass of Fe is :
  1. A
    55.85
  2. B
    55.95
  3. C
    55.75
  4. D
    56.05
View written solutionFree

Correct answer: B

The atomic mass of an element is the weighted average of the masses of its naturally occurring isotopes. The weighting factor for each isotope is its fractional abundance.

Step 1: Understand the formula for Average Atomic Mass

The average atomic mass is calculated using the following formula: Average Atomic Mass=∑(Isotopic Mass×Fractional Abundance)\text{Average Atomic Mass} = \sum (\text{Isotopic Mass} \times \text{Fractional Abundance})Average Atomic Mass=∑(Isotopic Mass×Fractional Abundance) We can approximate the isotopic mass with the given mass number for each isotope.

Step 2: List the given data

We are given the following information for the isotopes of Iron (Fe):

  • Isotope 1: 54^{54}54Fe
    • Mass Number ≈\approx≈ Isotopic Mass = 54 u
    • Abundance = 5%
  • Isotope 2: 56^{56}56Fe
    • Mass Number ≈\approx≈ Isotopic Mass = 56 u
    • Abundance = 90%
  • Isotope 3: 57^{57}57Fe
    • Mass Number ≈\approx≈ Isotopic Mass = 57 u
    • Abundance = 5%

Step 3: Convert percentage abundances to fractional abundances

To use the formula, we need to convert the percentage abundances into fractional (decimal) form by dividing by 100.

  • Fractional abundance of 54^{54}54Fe = 5/100=0.055 / 100 = 0.055/100=0.05
  • Fractional abundance of 56^{56}56Fe = 90/100=0.9090 / 100 = 0.9090/100=0.90
  • Fractional abundance of 57^{57}57Fe = 5/100=0.055 / 100 = 0.055/100=0.05

(Check: The sum of fractional abundances is 0.05+0.90+0.05=1.000.05 + 0.90 + 0.05 = 1.000.05+0.90+0.05=1.00, as expected.)

Step 4: Calculate the average atomic mass of Fe

Now, we plug the values into the formula:

Atomic Mass of Fe=(Mass of 54Fe×Abundance of 54Fe)+(Mass of 56Fe×Abundance of 56Fe)+(Mass of 57Fe×Abundance of 57Fe)\text{Atomic Mass of Fe} = (\text{Mass of } ^{54}\text{Fe} \times \text{Abundance of } ^{54}\text{Fe}) + (\text{Mass of } ^{56}\text{Fe} \times \text{Abundance of } ^{56}\text{Fe}) + (\text{Mass of } ^{57}\text{Fe} \times \text{Abundance of } ^{57}\text{Fe})Atomic Mass of Fe=(Mass of 54Fe×Abundance of 54Fe)+(Mass of 56Fe×Abundance of 56Fe)+(Mass of 57Fe×Abundance of 57Fe)

Atomic Mass of Fe=(54×0.05)+(56×0.90)+(57×0.05)\text{Atomic Mass of Fe} = (54 \times 0.05) + (56 \times 0.90) + (57 \times 0.05)Atomic Mass of Fe=(54×0.05)+(56×0.90)+(57×0.05)

Calculate each term:

  • 54×0.05=2.7054 \times 0.05 = 2.7054×0.05=2.70
  • 56×0.90=50.4056 \times 0.90 = 50.4056×0.90=50.40
  • 57×0.05=2.8557 \times 0.05 = 2.8557×0.05=2.85

Sum the terms to find the average atomic mass:

Atomic Mass of Fe=2.70+50.40+2.85=55.95 u\text{Atomic Mass of Fe} = 2.70 + 50.40 + 2.85 = 55.95 \text{ u}Atomic Mass of Fe=2.70+50.40+2.85=55.95 u

Step 5: Compare the result with the given options

The calculated atomic mass is 55.95.

  • A: 55.85
  • B: 55.95
  • C: 55.75
  • D: 56.05

The calculated value matches option B.

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