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Solutions question

2025 · Shift 2 · Q13
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Solutions question

2025 · Shift 2 · Q13

JEE AdvancedChemistrySolutionsNumerical+4 / −1
At 300 K , an ideal dilute solution of a macromolecule exerts osmotic pressure that is expressed in terms of the height (h)(h)(h) of the solution (density =1.00 g cm−3=1.00 \mathrm{~g} \mathrm{~cm}^{-3}=1.00 g cm−3) where hhh is equal to 2.00 cm . If the concentration of the dilute solution of the macromolecule is 2.00 gdm−32.00 \mathrm{~g} \mathrm{dm}^{-3}2.00 gdm−3, the molar mass of the macromolecule is calculated to be X×104 g mol−1\boldsymbol{X} \times 10^4 \mathrm{~g} \mathrm{~mol}^{-1}X×104 g mol−1. The value of X\boldsymbol{X}X is ‾\underline{\hspace{2cm}}​. Use: Universal gas constant (R)=8.3 J K−1 mol−1(R)=8.3 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}(R)=8.3 J K−1 mol−1 and acceleration due to gravity (g)=10 m s−2(g)=10 \mathrm{~m} \mathrm{~s}^{-2}(g)=10 m s−2
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