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Solutions question

2021 · Shift 1 · Q9
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Solutions question

2021 · Shift 1 · Q9

JEE AdvancedChemistrySolutionsNumerical+2 / −1
The boiling point of water in a 0.1 molal silver nitrate solution (solution A) is x ∘{}^\circ∘ C. To this solution A, an equal volume of 0.1 molal aqueous barium chloride solution is added to make a new solution B. The difference in the boiling points of water in the two solutions A and B is y ×\times× 10 −-− 2 ∘{}^\circ∘ C. (Assume : Densities of the solutions A and B are the same as that of water and the soluble salts dissociate completely. Use : Molal elevation constant (Ebullioscopic Constant), Kb = 0.5 K kg mol −-− 1; Boiling point of pure water as 100 ∘{}^\circ∘ C.)The value of x is ‾\underline{\hspace{2cm}}​.
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