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Solutions question

2017 · Shift 2 · Q1
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Solutions question

2017 · Shift 2 · Q1

JEE AdvancedChemistrySolutionsMCQ+3 / −0.75
Pure water freezes at 273K273K273K and 111 bar. The addition of 34.5g34.5g34.5g of ethanol to 500g500g500g of water changes the freezing point of the solution. Use the freezing point depression constant of water as 222 kg mol−1.mo{l^{ - 1}}.mol−1. The figures shown below represent plots of vapor pressure (V.P.)(V.P.)(V.P.) versus temperature (T).(T).(T).[molecular weight of ethanol is 46gmol−1.46gmo{l^{ - 1}}.46gmol−1. ] Among the following, the option representing change in the freezing point is
  1. A
    JEE Advanced 2017 Paper 2 Offline Chemistry - Solutions Question 15 English Option 1
  2. B
    JEE Advanced 2017 Paper 2 Offline Chemistry - Solutions Question 15 English Option 2
  3. C
    JEE Advanced 2017 Paper 2 Offline Chemistry - Solutions Question 15 English Option 3
  4. D
    JEE Advanced 2017 Paper 2 Offline Chemistry - Solutions Question 15 English Option 4
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