JEE AdvancedChemistrySolutionsMCQ+3 / −1
Properties such as boiling point, freezing point and vapour pressure of a pure solvent change when solute molecules are added to get homogeneous solution. These are called colligative properties. Applications of colligative properties are very useful in day-to-day life. One of its examples is the use of ethylene glycol and water mixture as anti-freezing liquid in the radiator of automobiles. A solution M is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is 0.9. Given: Freezing point depression constant of water K kg mol Freezing point depression constant of ethanol K kg mol Boiling point elevation constant of water K kg mol Boiling point elevation constant of ethanol K kg mol Standard freezing point of water = 273 K Standard freezing point of ethanol = 155.7 K Standard boiling point of water = 373 K Standard boiling point of ethanol = 351.5 K Vapour pressure of pure water = 32.8 mm Hg Vapour pressure of pure water = 40 mm Hg Molecular weight of water = 18 g mol Molecular weight of ethanol = 46 g mol In answering the following questions, consider the solutions to be ideal dilute solutions and solutes to be non-volatile and non-dissociative.The freezing point of the solution M is :
- A268.7 K
- B268.5 K
- C234.2 K
- D150.9 K
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