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P Block Elements question

2014 · Shift 2 · Q9
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P Block Elements question

2014 · Shift 2 · Q9

JEE AdvancedChemistryP Block ElementsMCQ+3 / −1
The product formed in the reaction of SOCl2SOCl_2SOCl2​ with white phosphorus is
  1. A
    PCl3PCl_3PCl3​
  2. B
    SO2Cl2SO_2Cl_2SO2​Cl2​
  3. C
    SCl2SCl_2SCl2​
  4. D
    POCl3POCl_3POCl3​
View written solutionFree

Correct answer: A

  1. We need the product formed when thionyl chloride, SOCl2SOCl_2SOCl2​, reacts with white phosphorus.

  2. Recall an important reaction of white phosphorus with thionyl chloride: P4+6SOCl2→4PCl3+3SO2+3S2Cl2P_4 + 6SOCl_2 \rightarrow 4PCl_3 + 3SO_2 + 3S_2Cl_2P4​+6SOCl2​→4PCl3​+3SO2​+3S2​Cl2​

This shows that phosphorus is converted into phosphorus trichloride, PCl3PCl_3PCl3​.

  1. Hence, among the given options, the product asked for is: PCl3PCl_3PCl3​

  2. Check options:

  • A: PCl3PCl_3PCl3​ — correct
  • B: SO2Cl2SO_2Cl_2SO2​Cl2​ — not the phosphorus product formed here
  • C: SCl2SCl_2SCl2​ — not the standard product in this reaction
  • D: POCl3POCl_3POCl3​ — not formed by direct reaction of white phosphorus with SOCl2SOCl_2SOCl2​

Therefore, the correct option is A.

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