Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

P Block Elements question

2009 · Shift 2 · Q8
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Advanced
  3. /Chemistry
  4. /P Block Elements
  5. /2009 · Shift 2 · Q8

P Block Elements question

2009 · Shift 2 · Q8

JEE AdvancedChemistryP Block ElementsMultiple correct+4 / −2
The nitrogen oxide(s) that contain(s) N-N bond(s) is(are)
  1. A
    N 2{}_22​ O
  2. B
    N 2{}_22​ O 3{}_33​
  3. C
    N 2{}_22​ O 4{}_44​
  4. D
    N 2{}_22​ O 5{}_55​
View written solutionFree

Correct answer: A, B, C

To determine which of the given nitrogen oxides contain an N-N bond, we need to analyze the molecular structure of each compound.

Step 1: Analyze the structure of N2_22​O (Dinitrogen monoxide)

The chemical formula for dinitrogen monoxide (also known as nitrous oxide) is N2_22​O. The molecule is linear and has two major resonance structures:

N≡N+−O−⟷−N=N+=O\text{N} \equiv \text{N}^+ - \text{O}^- \longleftrightarrow ^- \text{N} = \text{N}^+ = \text{O}N≡N+−O−⟷−N=N+=O

In both resonance structures, the two nitrogen atoms are directly bonded to each other. Therefore, N2_22​O contains an N-N bond.

Step 2: Analyze the structure of N2_22​O3_33​ (Dinitrogen trioxide)

The structure of N2_22​O3_33​ is unsymmetrical and can be thought of as an NO molecule bonded to an NO2_22​ molecule. The connectivity is O=N-NO2_22​. The Lewis structure shows a direct bond between the two nitrogen atoms:

O // O=N−N   O\begin{array}{ccc} & & \text{O} \ & & // \ \text{O} & = \text{N} - \text{N} \ & & \ \ & & \text{O} \end{array}​​O ​​// O​=N−N ​​  ​​O​

A more detailed Lewis structure showing one resonance form is O=N-N(=O)-O. This structure clearly indicates the presence of an N-N single bond. Therefore, N2_22​O3_33​ contains an N-N bond.

Step 3: Analyze the structure of N2_22​O4_44​ (Dinitrogen tetroxide)

N2_22​O4_44​ is the dimer of nitrogen dioxide (NO2_22​). Two NO2_22​ molecules combine by forming a bond between their nitrogen atoms. The structure is O2_22​N-NO2_22​. The Lewis structure for one of its resonance forms is:

OO ∣∣∣∣ −O−N+−N+−O−\begin{array}{ccc} \text{O} & & \text{O} \ || & & || \ {}^{-}\text{O} - \text{N}^{+} & - & \text{N}^{+} - \text{O}^{-} \end{array}O​​O ∣∣​​∣∣ −O−N+​−​N+−O−​

This structure clearly shows a covalent single bond between the two nitrogen atoms. Therefore, N2_22​O4_44​ contains an N-N bond.

Step 4: Analyze the structure of N2_22​O5_55​ (Dinitrogen pentoxide)

In the gaseous phase, N2_22​O5_55​ is a covalent molecule. Its structure consists of two NO2_22​ groups connected by a central oxygen atom, forming an oxygen bridge. The connectivity is O2_22​N-O-NO2_22​. The Lewis structure for one of its resonance forms is:

OO ∣∣∣∣ −O−N+−O−N+−O−\begin{array}{ccccc} \text{O} & & & & \text{O} \ || & & & & || \ {}^{-}\text{O} - \text{N}^{+} & - \text{O} - & \text{N}^{+} & - & \text{O}^{-} \end{array}O​​​​O ∣∣​​​​∣∣ −O−N+​−O−​N+​−​O−​

In this structure, the two nitrogen atoms are not directly bonded to each other; they are separated by an oxygen atom. In the solid state, it exists as an ionic compound, nitronium nitrate ([NO2_22​]+^++[NO3_33​]−^−−), which also lacks an N-N bond. Therefore, N2_22​O5_55​ does not contain an N-N bond.

Conclusion

Based on the structural analysis:

  • N2_22​O contains an N-N bond.
  • N2_22​O3_33​ contains an N-N bond.
  • N2_22​O4_44​ contains an N-N bond.
  • N2_22​O5_55​ does not contain an N-N bond.

Thus, the correct options are A, B, and C.

PreviousNext

More from P Block Elements

  • A solution of colourless salt H on boiling with excess NaOH produces a non-flammable gas. The gas evolution ceases after sometime. Upon addition of Zn dust to the same solution, the gas evolution restarts. The colourless salt(s) H is(are):2008 · Multiple correct
  • Statement 1 : Pb 4+ compounds are stronger oxidising agents than Sn 4+ compounds. and Statement 2 : The higher oxidation states for the group 14 elements are more stable for the heavier members of the group due to 'inert pair…2008 · MCQ
  • There are some deposits of nitrates and phosphates in earth's crust. Nitrates are more soluble in water. Nitrates are difficult to reduce under the laboratory conditions but microbes do it easily. Ammonia forms large number of complexes…2008 · MCQ
  • There are some deposits of nitrates and phosphates in earth's crust. Nitrates are more soluble in water. Nitrates are difficult to reduce under the laboratory conditions but microbes do it easily. Ammonia forms large number of complexes…2008 · MCQ
  • There are some deposits of nitrates and phosphates in earth's crust. Nitrates are more soluble in water. Nitrates are difficult to reduce under the laboratory conditions but microbes do it easily. Ammonia forms large number of complexes…2008 · MCQ
  • Statement 1 : In water, orthoboric acid behaves as a weak monobasic acid. Statement 2 : In water, orthoboric acid acts as a proton donor.2007 · MCQ
  • The noble gases have closed-shell electronic configuration and are monoatomic gases under normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other…2007 · MCQ
  • The noble gases have closed-shell electronic configuration and are monoatomic gases under normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other…2007 · MCQ