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Ionic Equilibrium question

2022 · Shift 2 · Q1
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  5. /2022 · Shift 2 · Q1

Ionic Equilibrium question

2022 · Shift 2 · Q1

JEE AdvancedChemistryIonic EquilibriumNumerical+3 / −1
Concentration of H2SO4\mathrm{H}_{2} \mathrm{SO}_{4}H2​SO4​ and Na2SO4\mathrm{Na}_{2} \mathrm{SO}_{4}Na2​SO4​ in a solution is 1M1 \mathrm{M}1M and 1.8×10−2M1.8 \times 10^{-2} \mathrm{M}1.8×10−2M, respectively. Molar solubility of PbSO4\mathrm{PbSO}_{4}PbSO4​ in the same solution is X×10−YM\mathrm{X} \times 10^{-\mathrm{Y}} \mathrm{M}X×10−YM(expressed in scientific notation). The value of YYY is ‾\underline{\hspace{2cm}}​. [Given: Solubility product of PbSO4(Ksp)=1.6×10−8\mathrm{PbSO}_{4}\left(K_{s p}\right)=1.6 \times 10^{-8}PbSO4​(Ksp​)=1.6×10−8. For H2SO4,Kal\mathrm{H}_{2} \mathrm{SO}_{4}, K_{a l}H2​SO4​,Kal​ is very large and Ka2=1.2×10−2]\left.K_{a 2}=1.2 \times 10^{-2}\right]Ka2​=1.2×10−2]
Numerical answer
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