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Ionic Equilibrium question

2018 · Shift 1 · Q9
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  5. /2018 · Shift 1 · Q9

Ionic Equilibrium question

2018 · Shift 1 · Q9

JEE AdvancedChemistryIonic EquilibriumNumerical+3 / −1
The solubility of a salt of weak acid (AB)(AB)(AB) at pH 3pH\,3pH3 is Y×10−3mol L−1.Y \times {10^{ - 3}}mol\,{L^{ - 1}}.Y×10−3molL−1. The value of YYY is ‾\underline{\hspace{2cm}}​. (Given that the value of solubility product of ABABAB (Ksp)=2×10−10\left( {{K_{sp}}} \right) = 2 \times {10^{ - 10}}(Ksp​)=2×10−10 and the value of ionization constant of HBHBHB(Ka)=1×10−8\left( {{K_a}} \right) = 1 \times {10^{ - 8}}(Ka​)=1×10−8)
Numerical answer
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