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Ionic Equilibrium question

2010 · Shift 1 · Q4
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  5. /2010 · Shift 1 · Q4

Ionic Equilibrium question

2010 · Shift 1 · Q4

JEE AdvancedChemistryIonic EquilibriumMultiple correct+3 / −0.75
Aqueous solution of HNO3HNO_3HNO3​, KOHKOHKOH and CH3COOHCH_3COOHCH3​COOH and CH3COONaCH_3COONaCH3​COONa of identical concentrations are provided. The pairs of solutions which form a buffer upon mixing is(are)
  1. A
    HNO3HNO_3HNO3​ and CH3COOHCH_3COOHCH3​COOH
  2. B
    KOHKOHKOH and CH3COONaCH_3COONaCH3​COONa
  3. C
    HNO3HNO_3HNO3​ and CH3COONaCH_3COONaCH3​COONa
  4. D
    CH3COOHCH_3COOHCH3​COOH and CH3COONaCH_3COONaCH3​COONa
View written solutionFree

Correct answer: C, D

Definition of a Buffer Solution

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or a weak base and its conjugate acid. It has the property of resisting a change in pH upon the addition of a small amount of a strong acid or a strong base.

An acidic buffer, relevant to this question, contains a weak acid and its conjugate base. This can be achieved in two primary ways:

  1. By directly mixing a weak acid with its salt (which provides the conjugate base). For example, mixing CH3COOHCH_3COOHCH3​COOH (weak acid) and CH3COONaCH_3COONaCH3​COONa (its salt, providing the conjugate base CH3COO−CH_3COO^-CH3​COO−).
  2. By partial neutralization. For example:
    • Mixing a weak acid with a strong base, where the weak acid is in molar excess. The reaction forms the conjugate base, leaving some of the weak acid unreacted.
    • Mixing the salt of a weak acid (the conjugate base) with a strong acid, where the salt is in molar excess. The reaction forms the weak acid, leaving some of the conjugate base unreacted.

Given solutions are: HNO3HNO_3HNO3​ (strong acid), KOHKOHKOH (strong base), CH3COOHCH_3COOHCH3​COOH (weak acid), and CH3COONaCH_3COONaCH3​COONa (salt of weak acid, provides conjugate base CH3COO−CH_3COO^-CH3​COO−).

Let's evaluate each option:

A: HNO3HNO_3HNO3​ and CH3COOHCH_3COOHCH3​COOH

  1. HNO3HNO_3HNO3​ is a strong acid.
  2. CH3COOHCH_3COOHCH3​COOH is a weak acid.
  3. Mixing a strong acid and a weak acid results in a solution containing both acids. There is no significant amount of a conjugate base present. The dissociation of the weak acid (CH3COOHCH_3COOHCH3​COOH) is suppressed due to the common ion effect from H+H^+H+ provided by the strong acid (HNO3HNO_3HNO3​). This mixture is not a buffer.

B: KOHKOHKOH and CH3COONaCH_3COONaCH3​COONa

  1. KOHKOHKOH is a strong base.
  2. CH3COONaCH_3COONaCH3​COONa provides the acetate ion (CH3COO−CH_3COO^-CH3​COO−), which is a weak base (the conjugate base of CH3COOHCH_3COOHCH3​COOH).
  3. Mixing a strong base and a weak base results in a strongly basic solution. There is no weak acid component to form a buffer pair. This mixture is not a buffer.

C: HNO3HNO_3HNO3​ and CH3COONaCH_3COONaCH3​COONa

  1. HNO3HNO_3HNO3​ is a strong acid.
  2. CH3COONaCH_3COONaCH3​COONa provides the conjugate base, CH3COO−CH_3COO^-CH3​COO−.
  3. When mixed, they react as follows: HNO3(aq)+CH3COONa(aq)→CH3COOH(aq)+NaNO3(aq)HNO_3(aq) + CH_3COONa(aq) \rightarrow CH_3COOH(aq) + NaNO_3(aq)HNO3​(aq)+CH3​COONa(aq)→CH3​COOH(aq)+NaNO3​(aq).
  4. The net ionic equation is: H+(aq)+CH3COO−(aq)→CH3COOH(aq)H^+(aq) + CH_3COO^-(aq) \rightarrow CH_3COOH(aq)H+(aq)+CH3​COO−(aq)→CH3​COOH(aq).
  5. To form a buffer, the final solution must contain both the weak acid (CH3COOHCH_3COOHCH3​COOH) and its conjugate base (CH3COO−CH_3COO^-CH3​COO−). This can be achieved if the strong acid (HNO3HNO_3HNO3​) is the limiting reactant, i.e., the initial moles of CH3COONaCH_3COONaCH3​COONa are greater than the initial moles of HNO3HNO_3HNO3​.
  6. For example, if we mix 2 moles of CH3COONaCH_3COONaCH3​COONa with 1 mole of HNO3HNO_3HNO3​, the reaction will produce 1 mole of CH3COOHCH_3COOHCH3​COOH, and 1 mole of CH3COONaCH_3COONaCH3​COONa will remain unreacted. The resulting solution contains a mixture of CH3COOHCH_3COOHCH3​COOH and CH3COONaCH_3COONaCH3​COONa, which is an acidic buffer.
  7. Since it is possible to form a buffer by mixing these two solutions in appropriate proportions, this option is correct.

D: CH3COOHCH_3COOHCH3​COOH and CH3COONaCH_3COONaCH3​COONa

  1. CH3COOHCH_3COOHCH3​COOH is a weak acid.
  2. CH3COONaCH_3COONaCH3​COONa is the salt of this weak acid with a strong base, and it provides the conjugate base CH3COO−CH_3COO^-CH3​COO−.
  3. Mixing a weak acid and its conjugate base is the direct method of preparing a buffer solution. The resulting solution will contain both species in concentrations dependent on the mixing ratio.
  4. This mixture is a classic example of an acidic buffer. Therefore, this option is correct.
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