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Electrochemistry question

2013 · Shift 2 · Q4

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JEE Advanced
Chemistry
Electrochemistry
2013 · Shift 2 · Q4

Electrochemistry question

2013 · Shift 2 · Q4

JEE AdvancedChemistryElectrochemistryMCQ+6 / −1.5

The standard reduction potential data at 25oC is given below: Eo (

Fe^{3+}

,

Fe^{2+}

) = +0.77V; Eo (

Fe^{2+}

,

Fe

) = -0.44V; Eo (

Cu^{2+}

,

Cu

) = +0.34V; Eo (

Cu^+

,

Cu

) = +0.52V; Eo [

O_2

(g) +

H^+

+ 4e-

\to

2

H_2O

] = +1.23V; Eo [

O_2

(g) + 2

H_2O

+ 4e-

\to

4

OH^-

] = +0.40 V Eo (

Cr^{3+}

,

Cr

) = -0.74V; Eo (

Cr^{2+}

,

Cr

) = -0.91V; Match Eo of the redox pair in List – I with the values given in List – II and select the correct answer using the code given below the lists: List - I P. Eo (

Fe^{3+}

,

Fe

) Q. Eo (4

H_2O

H^+

4

H^+

+ 4

OH^-

) R. Eo (

Cu^{2+}

+

Cu

\to

2

Cu^+

) S. Eo (

Cr^{3+}

,

Cr^{2+}

) List - II 1. -0.18 V 2. -0.4 V 3. -0.04 V 4. -0.83 V

A
P - 4; Q - 1; R - 2; S - 3
B
P - 2; Q - 3; R - 4; S - 1
C
P - 1; Q - 2; R - 3; S - 4
D
P - 3; Q - 4; R - 1; S - 2

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