Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents

Your guest activity stays on this device

Sign in to save progress →
Sign in

D and F Block Elements question

2019 · Shift 2 · Q5
Guest · filters and generic practice availableBrowsing as a guest · PYQ filters and generic practice are available. Sign in only for personalised features and saved progress.
  1. PYQ Library
  2. /JEE Advanced
  3. /Chemistry
  4. /D and F Block Elements
  5. /2019 · Shift 2 · Q5

D and F Block Elements question

2019 · Shift 2 · Q5

JEE AdvancedChemistryD and F Block ElementsMultiple correct+4 / −1
With reference to aqua-regia, choose the correct option(s).
  1. A
    Aqua-regia is prepared by mixing conc. HClHClHCl and conc. HNO3HNO_3HNO3​ in 3 : 1 (v / v) ratio
  2. B
    The yellow colour of aqua-regia is due to the presence of NOClNOClNOCl and Cl2Cl_2Cl2​
  3. C
    Reaction of gold with aqua-regia produces an anion having Au in +3 oxidation state
  4. D
    Reaction of gold with aqua regia produces NO2NO_2NO2​ in the absence of air
View written solutionFree

Correct answer: A, B, C

  1. What is aqua-regia?

Aqua-regia is a freshly prepared mixture of concentrated hydrochloric acid and concentrated nitric acid in the ratio: 3:1  (v/v)3:1 \; (v/v)3:1(v/v) So, Option A is correct.


  1. Why is aqua-regia yellow?

When conc. HClHClHCl and conc. HNO3HNO_3HNO3​ are mixed, they react to produce species such as nitrosyl chloride and chlorine: HNO3+3HCl→NOCl+Cl2+2H2OHNO_3 + 3HCl \rightarrow NOCl + Cl_2 + 2H_2OHNO3​+3HCl→NOCl+Cl2​+2H2​O Both NOClNOClNOCl and Cl2Cl_2Cl2​ contribute to the characteristic yellow/orange appearance of aqua-regia. Hence, Option B is correct.


  1. Reaction of gold with aqua-regia

Gold dissolves in aqua-regia because:

  • HNO3HNO_3HNO3​ oxidizes AuAuAu to Au3+Au^{3+}Au3+
  • Cl−Cl^-Cl− from HClHClHCl stabilizes it as a chloro-complex

The overall reaction is commonly written as: Au+HNO3+4HCl→HAuCl4+NO+2H2OAu + HNO_3 + 4HCl \rightarrow HAuCl_4 + NO + 2H_2OAu+HNO3​+4HCl→HAuCl4​+NO+2H2​O The anion formed is: [AuCl4]−[AuCl_4]^-[AuCl4​]− Now, for oxidation state of Au in [AuCl4]−[AuCl_4]^-[AuCl4​]−: Let oxidation state of Au be xxx. x+4(−1)=−1x + 4(-1) = -1x+4(−1)=−1 x−4=−1x - 4 = -1x−4=−1 x=+3x = +3x=+3 So, Option C is correct.


  1. Does gold with aqua-regia produce NO2NO_2NO2​ in absence of air?

From the standard reaction of gold with aqua-regia: Au+HNO3+4HCl→HAuCl4+NO+2H2OAu + HNO_3 + 4HCl \rightarrow HAuCl_4 + NO + 2H_2OAu+HNO3​+4HCl→HAuCl4​+NO+2H2​O The nitrogen oxide initially formed is NONONO, not NO2NO_2NO2​. NONONO may further oxidize in air to NO2NO_2NO2​: 2NO+O2→2NO22NO + O_2 \rightarrow 2NO_22NO+O2​→2NO2​ Therefore, in the absence of air, NO2NO_2NO2​ is not produced. So, Option D is incorrect.


  1. Final selection

Correct options are: A,  B,  C\boxed{A,\;B,\;C}A,B,C​


  1. Comparison with stored correct answer

Stored correct answer: A,B,CA, B, CA,B,C

My derived answer matches the stored answer.

PreviousNext

More from D and F Block Elements

  • Among the species given below, the total number of diamagnetic species is ​. H atom, NO2​ monomer, O2​−(superoxide), dimeric sulphur in vapor phase, Mn3​O4​, (NH4​)2​[FeCl4​],(NH4​)2​[NiCl4​],…2018 · Numerical
  • The correct option(s) to distinguish nitrate salts of Mn2+ and Cu2+ taken separately is (are)2018 · Multiple correct
  • Which of the following combination will produce H2​ gas ?2017 · MCQ
  • The options(s) with only amphoteric oxides is (are)2017 · Multiple correct
  • The reagent(s) that can selectively precipitate S2− from a mixture of S2− and SO42−​ in aqueous solution is (are) :2016 · Multiple correct
  • In the following reaction, sequence in aqueous solution, the species X, Y and Z, respectively, are S2​O32−​Ag+​ClearsolutionX​Ag+​WhiteprecipitateY​Withtime​BlackprecipitateZ​…2016 · MCQ
  • The correct statements about Cr2+ and Mn3+ is(are) (Atomic numbers of Cr = 24 and Mn = 25)2015 · Multiple correct
  • The pairs of ions where BOTH the ions are precipitated upon passing H2​S gas in presence of dilute HCl, is(are)2015 · Multiple correct