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Coordination Compounds question

2012 · Shift 1 · Q9
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Coordination Compounds question

2012 · Shift 1 · Q9

JEE AdvancedChemistryCoordination CompoundsMCQ+3 / −1
As per IUPAC nomenclature, the name of the complex [Co(H2O)4(NH3)2]Cl3[Co{({H_2}O)_4}{(N{H_3})_2}]C{l_3}[Co(H2​O)4​(NH3​)2​]Cl3​ is
  1. A
    Tetraaquadiaminecobalt (III) chloride.
  2. B
    Tetraaquadiamminecobalt (III) chloride.
  3. C
    Diaminetetraaquacobalt (III) chloride.
  4. D
    Diamminetetraaquacobalt (III) chloride.
View written solutionFree

Correct answer: D

The IUPAC nomenclature for coordination compounds follows a set of rules. Let's apply them to the complex [Co(H2O)4(NH3)2]Cl3[Co({H_2}O)_4{(N{H_3})_2}]C{l_3}[Co(H2​O)4​(NH3​)2​]Cl3​.

  1. Identify the Cation and Anion: The compound is ionic. The part in square brackets is the complex cation, and the chloride ions are the anions.

    • Cation: [Co(H2O)4(NH3)2]3+[Co({H_2}O)_4{(N{H_3})_2}]^{3+}[Co(H2​O)4​(NH3​)2​]3+
    • Anion: Cl−Cl^-Cl− The name of the cation is written first, followed by the name of the anion.
  2. Determine the Oxidation State of the Central Metal Ion: Let the oxidation state of Cobalt (Co) be xxx. The water ligand (H2OH_2OH2​O) and ammonia ligand (NH3NH_3NH3​) are neutral, so their charge is 0. The chloride ion (Cl−Cl^−Cl−) has a charge of -1. Since there are three chloride ions, their total charge is -3. The overall charge of the complex is 0. So, we can write the equation: x+4(0)+2(0)+3(−1)=0x + 4(0) + 2(0) + 3(-1) = 0x+4(0)+2(0)+3(−1)=0 x−3=0x - 3 = 0x−3=0 x=+3x = +3x=+3 The oxidation state of cobalt is +3, which is represented by Roman numeral (III).

  3. Name the Ligands: The ligands are named before the central metal ion.

    • H2OH_2OH2​O is named 'aqua'. Since there are four of them, we use the prefix 'tetra-', so it becomes 'tetraaqua'.
    • NH3NH_3NH3​ is named 'ammine'. Since there are two of them, we use the prefix 'di-', so it becomes 'diammine'.
  4. Order the Ligands Alphabetically: The ligands are listed in alphabetical order of their names (ignoring the numerical prefixes di-, tri-, tetra-, etc.).

    • 'ammine' comes before 'aqua' alphabetically.
    • So, the order is 'diammine' followed by 'tetraaqua'.
  5. Name the Central Metal Ion: The central metal is Cobalt (Co). Since the complex ion is a cation, the name of the metal is used as it is, followed by its oxidation state in Roman numerals in parentheses.

    • Metal name: cobalt
    • Oxidation state: (III)
    • So, it is 'cobalt(III)'.
  6. Assemble the Name of the Cation: Combining the ligand names (in alphabetical order) and the metal name: Diamminetetraaquacobalt(III)

  7. Combine the Cation and Anion Names: The full name of the compound is the name of the cation followed by the name of the anion, separated by a space.

    • Cation: Diamminetetraaquacobalt(III)
    • Anion: chloride (Note: we don't use prefixes like 'tri-' for simple anions).
    • Full Name: Diamminetetraaquacobalt (III) chloride.
  8. Evaluate the Options:

    • A: Tetraaquadiaminecobalt (III) chloride. Incorrect alphabetical order and misspelling of 'ammine'.
    • B: Tetraaquadiamminecobalt (III) chloride. Incorrect alphabetical order.
    • C: Diaminetetraaquacobalt (III) chloride. Misspelling of 'ammine'. The correct name for NH3NH_3NH3​ as a ligand is 'ammine' (with double 'm').
    • D: Diamminetetraaquacobalt (III) chloride. This matches our derived name perfectly.

Therefore, the correct IUPAC name is Diamminetetraaquacobalt (III) chloride.

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