- Aoctahedral, tetrahedral and square planar
- Btetrahedral, square planar and octahedral
- Csquare planar, tetrahedral, and octahedral
- Doctahedral, square planar and octahedral
View written solutionFree
Correct answer: B
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Identify the possible complexes of with the given ligands
Nickel(II) has electronic configuration:
The geometry depends on the ligand strength and coordination number.
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With
Chloride is a weak-field ligand. Nickel(II) with excess chloride commonly forms: This is a -coordinate complex of a weak-field ligand, so it is generally tetrahedral.
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With
Cyanide is a strong-field ligand. Nickel(II) with cyanide forms: For nickel(II) with a strong-field ligand, the complex is square planar.
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With
Water commonly forms the hexaaqua complex: This is a -coordinate complex, which is octahedral.
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Arrange the geometries in the required order
For , and respectively:
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Match with the options
This corresponds to Option B.
Therefore, the correct answer is B.
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