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Coordination Compounds question

2011 · Shift 1 · Q2
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Coordination Compounds question

2011 · Shift 1 · Q2

JEE AdvancedChemistryCoordination CompoundsMCQ+2 / −0.5
Geometrical shapes of the complexes formed by the reaction of Ni2+Ni^{2+}Ni2+ with Cl−Cl^-Cl−, CN−CN^-CN− and H2OH_2OH2​O respectively are
  1. A
    octahedral, tetrahedral and square planar
  2. B
    tetrahedral, square planar and octahedral
  3. C
    square planar, tetrahedral, and octahedral
  4. D
    octahedral, square planar and octahedral
View written solutionFree

Correct answer: B

  1. Identify the possible complexes of Ni2+Ni^{2+}Ni2+ with the given ligands

    Nickel(II) has electronic configuration: Ni2+:[Ar]3d8Ni^{2+} : [Ar]3d^8Ni2+:[Ar]3d8

    The geometry depends on the ligand strength and coordination number.

  2. With Cl−Cl^-Cl−

    Chloride is a weak-field ligand. Nickel(II) with excess chloride commonly forms: [NiCl4]2−[NiCl_4]^{2-}[NiCl4​]2− This is a 444-coordinate complex of a weak-field ligand, so it is generally tetrahedral.

  3. With CN−CN^-CN−

    Cyanide is a strong-field ligand. Nickel(II) with cyanide forms: [Ni(CN)4]2−[Ni(CN)_4]^{2-}[Ni(CN)4​]2− For d8d^8d8 nickel(II) with a strong-field ligand, the complex is square planar.

  4. With H2OH_2OH2​O

    Water commonly forms the hexaaqua complex: [Ni(H2O)6]2+[Ni(H_2O)_6]^{2+}[Ni(H2​O)6​]2+ This is a 666-coordinate complex, which is octahedral.

  5. Arrange the geometries in the required order

    For Cl−Cl^-Cl−, CN−CN^-CN− and H2OH_2OH2​O respectively: tetrahedral, square planar, octahedral\text{tetrahedral, square planar, octahedral}tetrahedral, square planar, octahedral

  6. Match with the options

    This corresponds to Option B.

Therefore, the correct answer is B.

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