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Coordination Compounds question

2009 · Shift 2 · Q17
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Coordination Compounds question

2009 · Shift 2 · Q17

JEE AdvancedChemistryCoordination CompoundsNumerical+3 / −1
The number of water molecule(s) directly bonded to the centre in CuSO 4{}_44​ . 5H 2{}_22​ O is ‾\underline{\hspace{2cm}}​.
Numerical answer
View written solutionFree

Correct answer: 4

  1. Identify the compound

    Copper(II) sulfate pentahydrate is written as: CuSO4⋅5H2O\mathrm{CuSO_4\cdot 5H_2O}CuSO4​⋅5H2​O

  2. Understand “directly bonded to the centre”

    Here, the “centre” is the metal ion Cu2+\mathrm{Cu^{2+}}Cu2+.

    In hydrated copper(II) sulfate, the actual structure is: [Cu(H2O)4]SO4⋅H2O\mathrm{[Cu(H_2O)_4]SO_4\cdot H_2O}[Cu(H2​O)4​]SO4​⋅H2​O

  3. Count the coordinated water molecules

    In [Cu(H2O)4]2+\mathrm{[Cu(H_2O)_4]^{2+}}[Cu(H2​O)4​]2+ the number of water molecules directly bonded (coordinated) to Cu2+\mathrm{Cu^{2+}}Cu2+ is: 444

  4. What about the 5th water molecule?

    The fifth water molecule is not directly bonded to copper. It is present as water of crystallization.

  5. Final answer

    Therefore, the number of water molecules directly bonded to the central metal ion in CuSO4⋅5H2O\mathrm{CuSO_4\cdot 5H_2O}CuSO4​⋅5H2​O is: 4\boxed{4}4​

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