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Compounds Containing Nitrogen question

2023 · Shift 2 · Q16
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Compounds Containing Nitrogen question

2023 · Shift 2 · Q16

JEE AdvancedChemistryCompounds Containing NitrogenNumerical+3 / −1
A trinitro compound, 1,3,5-tris-(4-nitrophenyl)benzene, on complete reaction with an excess of Sn/HCl\mathrm{Sn} / \mathrm{HCl}Sn/HCl gives a major product, which on treatment with an excess of NaNO2/HCl\mathrm{NaNO}_2 / \mathrm{HCl}NaNO2​/HCl at 0∘C0^{\circ} \mathrm{C}0∘C provides P\mathbf{P}P as the product. P\mathbf{P}P, upon treatment with excess of H2O\mathrm{H}_2 \mathrm{O}H2​O at room temperature, gives the product Q\mathbf{Q}Q. Bromination of Q\mathbf{Q}Q in aqueous medium furnishes the product R\mathbf{R}R. The compound P\mathbf{P}P upon treatment with an excess of phenol under basic conditions gives the product S\mathbf{S}S. The molar mass difference between compounds Q\mathbf{Q}Q and R\mathbf{R}R is 474 g mol−1474 \mathrm{~g} \mathrm{~mol}^{-1}474 g mol−1 and between compounds P\mathbf{P}P and S\mathbf{S}S is 172.5 g mol−1172.5 \mathrm{~g} \mathrm{~mol}^{-1}172.5 g mol−1.The number of heteroatoms present in one molecule of R\mathbf{R}R is ‾\underline{\hspace{2cm}}​. [Use : Molar mass (in gmol−1)\left.\mathrm{g} \mathrm{mol}^{-1}\right)gmol−1): H=1,C=12, N=14,O=16,Br=80,Cl=35.5\mathrm{H}=1, \mathrm{C}=12, \mathrm{~N}=14, \mathrm{O}=16, \mathrm{Br}=80, \mathrm{Cl}=35.5H=1,C=12, N=14,O=16,Br=80,Cl=35.5 Atoms other than C\mathrm{C}C and H\mathrm{H}H are considered as heteroatoms]
Numerical answer
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