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Compounds Containing Nitrogen question

2022 · Shift 1 · Q14
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Compounds Containing Nitrogen question

2022 · Shift 1 · Q14

JEE AdvancedChemistryCompounds Containing NitrogenMultiple correct+4 / −2
Considering the following reaction sequence, JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 14 English the correct option(s) is(are)
  1. A
    P=H2/Pd\mathbf{P}=\mathrm{H}_{2} / \mathrm{Pd}P=H2​/Pd, ethanol R=NaNO2/HClU=1.H3PO2\mathbf{R}=\mathrm{NaNO}_{2} / \mathrm{HCl}\mathbf{U}=1 . \mathrm{H}_{3} \mathrm{PO}_{2}R=NaNO2​/HClU=1.H3​PO2​ 2. KMnO4−KOH\mathrm{KMnO}_{4}-\mathrm{KOH}KMnO4​−KOH, heat
  2. B
    JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 14 English Option 2
  3. C
    JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 14 English Option 3
  4. D
    JEE Advanced 2022 Paper 1 Online Chemistry - Compounds Containing Nitrogen Question 14 English Option 4
View written solutionFree

Correct answer: A, B, C

The image/reaction scheme itself is missing from the text, so the full structure-based evaluation cannot be carried out directly from the provided prompt.

However, from the visible part of option A, the sequence is:

  1. P=H2/Pd\mathbf{P} = \mathrm{H_2/Pd}P=H2​/Pd in ethanol
  2. R=NaNO2/HCl\mathbf{R} = \mathrm{NaNO_2/HCl}R=NaNO2​/HCl
  3. U=(1) H3PO2 ; (2) KMnO4/KOH, heat\mathbf{U} = \left(1\right)\ \mathrm{H_3PO_2}\ ;\ \left(2\right)\ \mathrm{KMnO_4/KOH,\ heat}U=(1) H3​PO2​ ; (2) KMnO4​/KOH, heat

This is a very standard sequence for aromatic nitro/amine/diazonium chemistry:

  • H2/Pd\mathrm{H_2/Pd}H2​/Pd reduces a nitro group to an amine.
  • NaNO2/HCl\mathrm{NaNO_2/HCl}NaNO2​/HCl converts a primary aromatic amine to a diazonium salt.
  • H3PO2\mathrm{H_3PO_2}H3​PO2​ replaces the diazonium group by hydrogen (deamination).
  • Hot alkaline KMnO4\mathrm{KMnO_4}KMnO4​ oxidizes an alkyl side chain on benzene to a carboxylic acid (or carboxylate under basic conditions).

So option A is chemically consistent.

Since the actual reaction sequence/structures and the full contents of options B, C, and D are not visible, a rigorous independent derivation of B and C is impossible from the supplied text alone.

Given that the stored correct answer is A,B,CA, B, CA,B,C, and the visible chemistry in A is valid, the best possible conclusion from the provided information is to accept the stored answer.

Final answer

Correct options: A,B,CA, B, CA,B,C

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