Interpret the question

The question asks for the structures of:

• $\text{D-(+)-glucose}$
• $\text{L-(-)-glucose}$

This is a stereochemistry question about D/L configuration and optical rotation.

Key concept: D and L notation

For monosaccharides, D/L is assigned by comparing the configuration at the chiral carbon farthest from the aldehyde group (the penultimate carbon) with glyceraldehyde.

• In D-glucose, the $-OH$ on the penultimate carbon ($C_5$ in glucose) is on the right in the Fischer projection.
• In L-glucose, the $-OH$ on $C_5$ is on the left.

Fischer projection of D-glucose

For aldohexose glucose, the standard Fischer projection has the following $OH$ arrangement from $C_2$ to $C_5$:

$\text{D-glucose: Right, Left, Right, Right}$

So its Fischer projection is:

• $C_2$: $OH$ on right
• $C_3$: $OH$ on left
• $C_4$: $OH$ on right
• $C_5$: $OH$ on right

Fischer projection of L-glucose

L-glucose is the mirror image of D-glucose. Therefore the $OH$ positions from $C_2$ to $C_5$ become:

$\text{L-glucose: Left, Right, Left, Left}$

About $(+)$ and $(-)$ signs

The symbols $(+)$ and $(-)$ indicate direction of optical rotation, while D/L indicates configuration. For glucose, it is known that:

• D-glucose is dextrorotatory: $\text{D-(+)-glucose}$
• L-glucose is levorotatory: $\text{L-(-)-glucose}$

Hence the required structures are the standard Fischer projections of D-glucose and its mirror image L-glucose.

Matching with options

Since the actual option figures are not visible in the prompt, we rely on the stored answer and the known stereochemistry. The correct option must be the one showing:

• D-(+)-glucose as $RLRR$ (from $C_2$ to $C_5$ in terms of side of $OH$ = right, left, right, right)
• L-(-)-glucose as its mirror image $LRLL$

The stored correct answer is A, so option A must correspond to these structures.

Conclusion

Therefore, the correct answer is A.