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Basics of Organic Chemistry question

2021 · Shift 2 · Q14
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Basics of Organic Chemistry question

2021 · Shift 2 · Q14

JEE AdvancedChemistryBasics of Organic ChemistryMCQ+3 / −1
The amount of energy required to break a bond is same as the amount of energy released when the same bond is formed. In gaseous state, the energy required for homolytic cleavage of a bond is called Bond Dissociation Energy (BDE) or Bond Strength. BDE is affected by s-character of the bond and the stability of the radicals formed. Shorter bonds are typically stronger bonds. BDEs for some bonds are given below : JEE Advanced 2021 Paper 2 Online Chemistry - Basics of Organic Chemistry Question 26 English Comprehension ClClCl −-− ClClCl (g) →\to→ ClClCl (g)∙{}_{(g)}^ \bullet(g)∙​ + ClClCl (g)∙Δ{}_{(g)}^ \bullet \Delta(g)∙​Δ H ∘{}^\circ∘ = 58 kcal mol −-− 1 H3CH_3CH3​C −-− ClClCl (g) →\to→ H3CH_3CH3​C (g)∙{}_{(g)}^ \bullet(g)∙​ + ClClCl (g)∙Δ{}_{(g)}^ \bullet \Delta(g)∙​Δ H ∘{}^\circ∘ = 85 kcal mol −-− 1 HHH −-− ClClCl (g) →\to→ HHH (g)∙{}_{(g)}^ \bullet(g)∙​ + ClClCl (g)∙Δ{}_{(g)}^ \bullet \Delta(g)∙​Δ H ∘{}^\circ∘ = 103 kcal mol −-− 1For the following reaction CH4CH_4CH4​(g) + Cl2Cl_2Cl2​(g) →light\xrightarrow{light}light​ CH3ClCH_3ClCH3​Cl(g) + HClHClHCl (g) the correct statement is
  1. A
    Initiation step is exothermic with Δ\DeltaΔ H ∘{}^\circ∘=−-− 58 kcal mol −-− 1.
  2. B
    Propagation step involving ∙CH3{}^ \bullet C{H_3}∙CH3​ formation is exothermic with Δ\DeltaΔ H ∘{}^\circ∘=−-− 2 kcal mol −-− 1.
  3. C
    Propagation step involving CH3ClCH_3ClCH3​Cl formation is endothermic with Δ\DeltaΔ H ∘{}^\circ∘ = +27 kcal mol −-− 1.
  4. D
    The reaction is exothermic with Δ\DeltaΔ H ∘{}^\circ∘=−-− 25 kcal mol −-− 1.
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