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Chemical and Phase Equilibria question

2018 · Q59
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Chemical and Phase Equilibria question

2018 · Q59

IIT JAMChemistryChemical and Phase EquilibriaNumerical+2 / −0
The solubility of PbI 2_22​ in 0.10 M KI(aq) is ‾×\underline{\hspace{2cm}}\times​× 10 −7^{-7}−7 M (rounded up to two decimal places). [The solubility product, Ksp=7.1×10−9K_{sp} = 7.1\times10^{-9}Ksp​=7.1×10−9]
Numerical answer
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Correct answer: 7.0, 7.2

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