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Chemical and Phase Equilibria question

2015 · Q24
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Chemical and Phase Equilibria question

2015 · Q24

IIT JAMChemistryChemical and Phase EquilibriaMCQ+2 / −0.67
At 25 °C, the solubility product (KspK_{sp}Ksp​) of CaF 2_22​ in water is 3.2×10−113.2 \times 10^{-11}3.2×10−11. The solubility (in mole per kg of water) of the salt at the same temperature (ignore ion pairing) is
  1. A
    4.0×10−64.0 \times 10^{-6}4.0×10−6
  2. B
    3.2×10−43.2 \times 10^{-4}3.2×10−4
  3. C
    2.5×10−42.5 \times 10^{-4}2.5×10−4
  4. D
    2.0×10−42.0 \times 10^{-4}2.0×10−4
View written solutionFree

Correct answer: D

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