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Work Energy and Power question

2006 · Q160
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Work Energy and Power question

2006 · Q160

NEETPhysicsWork Energy and PowerMCQ+4 / −1
A body of mass 3 kg is under a constant force which causes a displacement s in metres in it, given by the relation s = 13{1 \over 3}31​t2, where t is in seconds. Work done by the force in 2 seconds is
  1. A
    195J{{19} \over 5}J519​J
  2. B
    519J{5 \over {19}}J195​J
  3. C
    38J{3 \over {8}}J83​J
  4. D
    83J{8 \over {3}}J38​J
View written solutionFree

Correct answer: D

Acceleration = d2s/dt2
= 2/3 m/s2

Now force acting on body = mass × acceleration

F = 3 × (2/3) = 2 Newton

Hence displacement in 2 secs
= (1/3) × 2 × 2 = 4/3 m

Finally, work done = 2 × 4/3 = 8/3 J

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