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Waves question

2017 · Q163
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Waves question

2017 · Q163

NEETPhysicsWavesMCQ+4 / −1
The two nearest harmonics of a tube closed at one end and open at other end are 220 Hz and 260 Hz. What is the fundamental frequency of the system ?
  1. A
    20 Hz
  2. B
    30 Hz
  3. C
    40 Hz
  4. D
    10 Hz
View written solutionFree

Correct answer: A

The difference of frequencies of closed pipe
2v4l=260−220=40 Hz{{2v} \over {4l}} = 260 - 220 = 40\,Hz4l2v​=260−220=40Hz

So, the fundamental frequency f′=v4l=20 Hzf' = {v \over {4l}} = 20\,Hzf′=4lv​=20Hz

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