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Waves question

2015 · Q108
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Waves question

2015 · Q108

NEETPhysicsWavesMCQ+4 / −1
A string is stretched between fixed points separated by 75.0 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. The lowest resonant frequency for this string is
  1. A
    10.5 Hz
  2. B
    105 Hz
  3. C
    155 Hz
  4. D
    205 Hz
View written solutionFree

Correct answer: B

In a stretched string all multiples of frequencies can be obtained i.e., if fundamental frequency is n then higher frequencies will be 2n, 3n, 4n ...

AIPMT 2015 Physics - Waves Question 53 English Explanation


So, the difference between any two successive frequencies will be 'n'

According to question, n = 420 – 315 = 105Hz

So the lowest frequency of the string is 105 Hz.

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