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Waves question

2008 · Q163
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Waves question

2008 · Q163

NEETPhysicsWavesMCQ+4 / −1
The wave described by y = 0.25 sin(10π\piπx −-− 2π\piπt), where x and y are in metres and t in seconds, is a wave travelling along the
  1. A
    +ve x direction with frequency 1 Hz and wavelength λ\lambdaλ = 0.2 m.
  2. B
    −-−ve x direction with amplitude 0.25 m and wavelength λ\lambdaλ = 0.2 m.
  3. C
    −-−ve x direction with frequency 1 Hz.
  4. D
    +ve x direction with frequency π\piπ Hz and wavelength λ\lambdaλ = 0.2 m.
View written solutionFree

Correct answer: A

y = 0.25sin(10π\pi πx – 2π\pi πt)

ymax⁡=0.25{y_{\max }} = 0.25ymax​=0.25

k=2πλ=10π⇒λ=0.2 mk = {{2\pi } \over \lambda } = 10\pi \Rightarrow \lambda = 0.2\,mk=λ2π​=10π⇒λ=0.2m

ω=2πf=2π⇒f=1 Hz\omega = 2\pi f = 2\pi \Rightarrow f = 1\,Hzω=2πf=2π⇒f=1Hz

The sign is negative inside the bracket. Therefore this wave travels in the positive x-direction.

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