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Units and Measurement question

2018 · Q116
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Units and Measurement question

2018 · Q116

NEETPhysicsUnits and MeasurementMCQ+4 / −1
A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of –0.004 cm, the correct diameter of the ball is
  1. A
    0.521 cm
  2. B
    0.525 cm
  3. C
    0.053 cm
  4. D
    0.529 cm
View written solutionFree

Correct answer: D

Diameter of the ball

= MSR + CSR × (Least count) – Zero error

= 5 mm + 25 × 0.001 cm – (–0.004) cm

= 0.5 cm + 25 × 0.001 cm – (–0.004) cm = 0.529 cm.

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