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Units and Measurement question

2013 · Q162
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Units and Measurement question

2013 · Q162

NEETPhysicsUnits and MeasurementMCQ+4 / −1
If an experiment four quantities a, b, c and d are measured with percentage error 1%, 2%, 3% and 4% respectively.

Quantity P is calculated as follows P =a3b2cd= {{{a^3}{b^2}} \over {cd}}=cda3b2​ % error in P is
  1. A
    7%
  2. B
    4%
  3. C
    14%
  4. D
    10%
View written solutionFree

Correct answer: C

Given P =a3b2cd = {{{a^3}{b^2}} \over {cd}}=cda3b2​

% error in P :

ΔPP×100{{\Delta P} \over P} \times 100PΔP​×100 = [3Δaa+2Δbb+Δcc+Δdd]×100\left[ {3{{\Delta a} \over a} + 2{{\Delta b} \over b} + {{\Delta c} \over c} + {{\Delta d} \over d}} \right] \times 100[3aΔa​+2bΔb​+cΔc​+dΔd​]×100

                  = 3 ×\times× 1% + 2 ×\times× 2% + 3% + 4% = 14%

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