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Units and Measurement question

2011 · Q168
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Units and Measurement question

2011 · Q168

NEETPhysicsUnits and MeasurementMCQ+4 / −1
The dimensions of (μ0ε0)−1/2{\left( {{\mu _0}{\varepsilon _0}} \right)^{ - 1/2}}(μ0​ε0​)−1/2 are
  1. A
    [L1/2T−1/2]\left[ {{L^{1/2}}{T^{ - 1/2}}} \right][L1/2T−1/2]
  2. B
    [L−1T]\left[ {{L^{ - 1}}T} \right][L−1T]
  3. C
    [LT−1]\left[ {L{T^{ - 1}}} \right][LT−1]
  4. D
    [L1/2T1/2]\left[ {{L^{1/2}}{T^{1/2}}} \right][L1/2T1/2]
View written solutionFree

Correct answer: C

(μ0ε0)−1/2{\left( {{\mu _0}{\varepsilon _0}} \right)^{ - 1/2}}(μ0​ε0​)−1/2 = 1μ0ε0{1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}μ0​ε0​​1​ = Speed of light in vacuum = c

So the dimension of (μ0ε0)−1/2{\left( {{\mu _0}{\varepsilon _0}} \right)^{ - 1/2}}(μ0​ε0​)−1/2 = [c] =[LT-1]

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