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Semiconductor Electronics question

2008 · Q143
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Semiconductor Electronics question

2008 · Q143

NEETPhysicsSemiconductor ElectronicsMCQ+4 / −1
A p-n photodiode is made of a material with a band gap of 2.0 eV. The minimum frequency of the radiation that can be absorbed by the material is nearly
  1. A
    1 ×\times× 1014 Hz
  2. B
    20 ×\times× 1014 Hz
  3. C
    10 ×\times× 1014 Hz
  4. D
    5 ×\times× 1014 Hz
View written solutionFree

Correct answer: D

Energy gap Eg = 2.0 eV

Eg = 2.0 × 1.6 × 10–19 J

Eg = hf

f = frequency of radiation

∴\therefore∴ f = Egh{{{E_g}} \over h}hEg​​

= 3.2×10−196.625×10−34{{3.2 \times {{10}^{ - 19}}} \over {6.625 \times {{10}^{ - 34}}}}6.625×10−343.2×10−19​

= 5 ×\times× 1014 Hz

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