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Semiconductor Electronics question

2007 · Q150
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Semiconductor Electronics question

2007 · Q150

NEETPhysicsSemiconductor ElectronicsMCQ+4 / −1
In the following circuit, the output Y for all possible inputs A and B is expressed by the truth table.

AIPMT 2007 Physics - Semiconductor Electronics Question 64 English
  1. A
    A&B&Y0&0&10&1&11&0&11&1&0\begin{matrix} A \& B \& Y \\ 0 \& 0 \& 1 \\ 0 \& 1 \& 1 \\ 1 \& 0 \& 1 \\ 1 \& 1 \& 0 \\ \end{matrix}A&B&Y0&0&10&1&11&0&11&1&0​
  2. B
    A&B&Y0&0&10&1&01&0&01&1&0\begin{matrix} A \& B \& Y \\ 0 \& 0 \& 1 \\ 0 \& 1 \& 0 \\ 1 \& 0 \& 0 \\ 1 \& 1 \& 0 \\ \end{matrix}A&B&Y0&0&10&1&01&0&01&1&0​
  3. C
    A&B&Y0&0&00&1&11&0&11&1&1\begin{matrix} A \& B \& Y \\ 0 \& 0 \& 0 \\ 0 \& 1 \& 1 \\ 1 \& 0 \& 1 \\ 1 \& 1 \& 1 \\ \end{matrix}A&B&Y0&0&00&1&11&0&11&1&1​
  4. D
    A&B&Y0&0&00&1&01&0&01&1&1\begin{matrix} A \& B \& Y \\ 0 \& 0 \& 0 \\ 0 \& 1 \& 0 \\ 1 \& 0 \& 0 \\ 1 \& 1 \& 1 \\ \end{matrix}A&B&Y0&0&00&1&01&0&01&1&1​
View written solutionFree

Correct answer: C

Y' = A+B‾\overline {A + B} A+B​

Y = Y′‾\overline {Y'} Y′

Y = A+B‾‾\overline{\overline {A + B}} A+B​​

Y = A + B which is OR-gate.

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