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Properties of Matter question

2016 · Q154
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Properties of Matter question

2016 · Q154

NEETPhysicsProperties of MatterMCQ+4 / −1
A black body is at a temperature of 5760 K. The energy of radiation emitted by the body at wavelength 250 nm is U1, at wavelength 500 nm is U2 and that at 1000 nm is U3. Wien's constant, b = 2.88 ×\times× 106 nm K. Which of the following is correct ?
  1. A
    U1 > U2
  2. B
    U2 > U1
  3. C
    U1 = 0
  4. D
    U3 = 0
View written solutionFree

Correct answer: B

According to wein's displacement law, maximum amount of emitted radiation corresponding to

λm=bT{\lambda _m} = {b \over T}λm​=Tb​

λm=2.88×106nmK5760K=500 nm{\lambda _m} = {{2.88 \times {{10}^6}nmK} \over {5760K}} = 500\,nmλm​=5760K2.88×106nmK​=500nm

NEET 2016 Phase 1 Physics - Properties of Matter Question 71 English Explanation


From the graph U1 < U2 > U3

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