NEETPhysicsOscillationsMCQ+4 / −1
Identify the function which represents a non-periodic motion.
- A
- B
- C
- D
View written solutionFree
Correct answer: B
Here,
$\sin \omega t$ and $$\sin \left( {\omega t + {\pi \over 4}} \right)$$ clearly suggest a periodic sinusoidal function (SHM)
And $$\sin \omega t + \cos \omega t = \sqrt 2 \sin \left( {\omega t + {\pi \over 4}} \right)$$ is also a periodic sinusoidal function (SHM)
While, $$y = {e^{ - \omega t}}$$ is an exponentially decreasing function and thus does not have periodicity.
More from Oscillations
- Two pendulums of length 121 cm and 100 cm start vibrating in phase. At some instant, the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at…2022 · MCQ
- A body is executing simple harmonic motion with frequency 'n', the frequency of its potential energy is :2021 · MCQ
- A spring is stretched by 5 cm by a force 10 N. The time period of the oscillations when a mass of 2 kg is suspended by it is -2021 · MCQ
- The phase difference between displacement and acceleration of a particle in a simple harmonic motion is :2020 · MCQ
- The radius of circle, the period of revolution, initial position and sense of revolution are indicated is the figure. y- projection of the radius vector of rotating particle P is : Includes diagram2019 · MCQ
- Average velocity of a particle executing SHM in one complete vibration is :2019 · MCQ
- The displacement of a particle executing simple harmonic motion is given by y = A0 + A sint + B cost. Then the amplitude of its oscillation is given by :2019 · MCQ
- A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m s–2 at a distance of 5 m from the mean position. The…2018 · MCQ