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Oscillations question

2022 · Q142
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Oscillations question

2022 · Q142

NEETPhysicsOscillationsMCQ+4 / −1

Match List-I with List-II

List-I
(x-y graphs)		 List-II
(Situations)
(a) NEET 2022 Phase 2 Physics - Oscillations Question 9 English 1 (i) Total mechanical energy is conserved
(b) NEET 2022 Phase 2 Physics - Oscillations Question 9 English 2 (ii) Bob of a pendulum is oscillating under negligible air friction
(c) NEET 2022 Phase 2 Physics - Oscillations Question 9 English 3 (iii) Restoring force of a spring
(d) NEET 2022 Phase 2 Physics - Oscillations Question 9 English 4 (iv) Bob of a pendulum is oscillating along with air friction

Choose the correct answer from the options given below

  1. A
    (a) - (iii), (b) - (ii), (c) - (i), (d) - (iv)
  2. B
    (a) - (iv), (b) - (ii), (c) - (iii), (d) - (i)
  3. C
    (a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)
  4. D
    (a) - (i), (b) - (iv), (c) - (iii), (d) - (ii)
View written solutionFree

Correct answer: C

(a)

NEET 2022 Phase 2 Physics - Oscillations Question 9 English Explanation 1

Amplitude of oscillation is continuously decreasing. It means bob of pendulum oscillate with air friction.

(b)

NEET 2022 Phase 2 Physics - Oscillations Question 9 English Explanation 2

$F = - kx$ (restoring force of a spring)

(c)

NEET 2022 Phase 2 Physics - Oscillations Question 9 English Explanation 3

Amplitude of oscillation is remains same. It means bob of pendulum is oscillating under negligible air resistance.

(d)

NEET 2022 Phase 2 Physics - Oscillations Question 9 English Explanation 4

$$P.E. = {1 \over 2}k{x^2},\,K.E. = {1 \over 2}m{\omega ^2}{A^2} - {1 \over 2}k{x^2}$$

$$T.E. = {1 \over 2}m{\omega ^2}{A^2} = $$ constant

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