NEETPhysicsMotion in A Straight LineMCQ+4 / −1
A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s, then the maximum height attained by it (g = 10 m/s2)
- A8 m
- B20 m
- C10 m
- D16 m
View written solutionFree
Correct answer: C
At height , speed is = 10 m/s
and at height h, speed = 0
Using formula,
v2 = u2 - 2gh
0 = (10)2 - 2(10)
h = = 10 m
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