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Motion in A Straight Line question

2000 · Q145
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Motion in A Straight Line question

2000 · Q145

NEETPhysicsMotion in A Straight LineMCQ+4 / −1
Motion of a particle is given by equation s = (3t3 + 7t2 + 14t + 8) m. The value of acceleration of the particle at t = 1 sec is
  1. A
    10 m/s2
  2. B
    32 m/s2
  3. C
    23 m/s2
  4. D
    16 m/s2
View written solutionFree

Correct answer: B

Given, s = (3t3 + 7t2 + 14t + 8)

dsdt{{ds} \over {dt}}dtds​ = 9t2 + 14t + 14

d2sdt2{{{d^2}s} \over {d{t^2}}}dt2d2s​ = 18t + 14

aaa = 18t + 14

At t = 1, a = 18 ×\times× 1 + 14 = 32 m/s2

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