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Magnetism and Matter question

2009 · Q139
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Magnetism and Matter question

2009 · Q139

NEETPhysicsMagnetism and MatterMCQ+4 / −1
A bar magnet having a magnetic moment of 2 ×\times× 104 J T−-−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 ×\times× 10−-−4 T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60o from the field is
  1. A
    12 J
  2. B
    6 J
  3. C
    2 J
  4. D
    0.6 J
View written solutionFree

Correct answer: B

Now work done = MB(cosθ1 – cosθ2)

= MB (1 – 1/2) = 2×104×6×10−42{{2 \times {{10}^4} \times 6 \times {{10}^{ - 4}}} \over 2}22×104×6×10−4​ = 6 J

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