A light ray enters through a right angled prism at point with the angle of incidence as shown in figure. It travels through the prism parallel to its base and emerges along the face . The refractive index of the prism is:

- A
- B
- C
- D
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Correct answer: B

In prism, $r_1+c=A$
$$\begin{aligned} \quad \& r_1=90^{\circ}-c \quad \text{.... (1)}\\ \& \sin c=\frac{1}{\mu} \Rightarrow \cos c=\frac{\sqrt{\mu^2-1}}{\mu} \end{aligned}$$
$\Rightarrow$ Apply Snell's law, on incidence surface
$$\begin{aligned} 1 \cdot \sin 30^{\circ}=\mu \sin \left(r_1\right) \Rightarrow 1 \times \frac{1}{2}=\mu \times \sin \left(90^{\circ}-c\right) \\ \frac{1}{2}=\mu \times \frac{\sqrt{\mu^2-1}}{\mu} \end{aligned}$$
On squaring $\frac{1}{4}=\mu^2-1$
$$\Rightarrow \mu^2=\frac{5}{4} \Rightarrow \mu=\frac{\sqrt{5}}{2}$$
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