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Electrostatics question

2013 · Q123
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Electrostatics question

2013 · Q123

NEETPhysicsElectrostaticsMCQ+4 / −1
An electric dipole of dipole moment p is aligned parallel to a uniform electric field E. The energy required to rotate the dipole by 90o is
  1. A
    p2 E
  2. B
    pE
  3. C
    infinity
  4. D
    pE2
View written solutionFree

Correct answer: B

Potential energy of dipole,
U=−pE(cos⁡θ2−cos⁡θ1)U = - pE\left( {\cos {\theta _2} - \cos {\theta _1}} \right)U=−pE(cosθ2​−cosθ1​)

Here, θ1=0o,θ2=90o{\theta _1} = {0^o},{\theta _2} = {90^o}θ1​=0o,θ2​=90o

∴\therefore∴ U = – pE(cos90° – cos0°) = – pE(0 – 1) = pE

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