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Electrostatics question

2012 · Q94
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Electrostatics question

2012 · Q94

NEETPhysicsElectrostaticsMCQ+4 / −1
Two metallic spheres of radii 1 cm and 3 cm are given charges of −-−1 ×\times× 10−-−2 C and 5 ×\times× 10−-−2 C, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is
  1. A
    2 ×\times× 10−-−2 C
  2. B
    3 ×\times× 10−-−2 C
  3. C
    4 ×\times× 10−-−2 C
  4. D
    1 ×\times× 10−-−2 C
View written solutionFree

Correct answer: B

At equilibrium potential of both sphere becomes same if charge of sphere one x and other sphere Q – x
then where Q = 4 × 10–2 C

v1 = v2

kx1 cm=k(Q−x)3 cm{{kx} \over {1\,cm}} = {{k\left( {Q - x} \right)} \over {3\,cm}}1cmkx​=3cmk(Q−x)​

3x = Q – x ⇒\Rightarrow⇒ 4x = Q

x=Q4=4×10−24C=1×10−2x = {Q \over 4} = {{4 \times {{10}^{ - 2}}} \over 4}C = 1 \times {10^{ - 2}}x=4Q​=44×10−2​C=1×10−2

Q' = Q – x = 3 × 10–2 C

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