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Electrostatics question

2011 · Q164
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Electrostatics question

2011 · Q164

NEETPhysicsElectrostaticsMCQ+4 / −1
A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will
  1. A
    increase four times
  2. B
    be reduced to half
  3. C
    remain the same
  4. D
    be doubled
View written solutionFree

Correct answer: C

According to Gauss’s law

ϕE=Qenclosedε0{\phi _E} = {{{Q_{enclosed}}} \over {{\varepsilon _0}}}ϕE​=ε0​Qenclosed​​

If the radius of the Gaussian surface is doubled, the outward electric flux will remain the same. This is because electric flux depends only on the charge enclosed by the surface.

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